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You're in the park with a few of your friends and you want to play a game of football. You decide that the most fair way to split up the teams is to have an even number of boys and girls on each...
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Incorrect 4 - Finding the Limiting Reagent
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Finding the Limiting Reagent. Find the limiting reagent if 98.7 grams of C4H10S2 were reacted with 386 grams of O2. 2C4H10S2 19O2= 8CO2 10H2O 4SO3. First we find the GFW of each reactant. Next we divide the number of grams of each reactant by the GFW. Finally, we multiply each of the results by the coefficient of the other reactant/. O809 x 19= 15.37. 1206 x 2= 24.12. Because 15.37 is smaller than 24.12, we know that the limiting reagent is C4H10S2. Create a free website.
Incorrect 2:3 - Finding the Limiting Reagent
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Finding the Limiting Reagent. How many grams of CO2 would be produced if 2.58 grams of C2H3OCl were reacted with 1.16 grams of CO2? C2H3OCl 2O2- 2CO2 H2O HCl. First we find the limiting reagent. Next we put the coefficient of the limiting reagent and the product into a ratio. Next we divide this by the coefficient of the limiting reagent. We then multiply the second number in the ratio by the number of moles in the limiting reagent. 1 x 0036= 0.036. 0036 x 44= 1.584 grams. That final number is your answer.
Incorrect 10 - Finding the Limiting Reagent
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Finding the Limiting Reagent. Find the limiting reagent if 6.59 grams of C2H3OF were reacted with 3.40 grams of O2. 4C2H3OF 5O2= 8O 6H2O 2F2. First we find the GFW of each reactant. Next we divide the number of grams of each reactant by the GFW. Finally, we multiply each of the results by the coefficient of the other reactant/. Because 0.424 is smaller than 0.53, we know that the limiting reagent is O2. Create a free website.
Incorrect 2:1 - Finding the Limiting Reagent
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Finding the Limiting Reagent. How many grams of CO2 would be produced if 64.2 grams of C4H10O were reacted with 290 grams of O2? C4H10O 6O2- 4CO2 5H2O. First we find the limiting reagent. Next we put the coefficient of the limiting reagent and the product into a ratio. Next we divide this by the coefficient of the limiting reagent. We then multiply the second number in the ratio by the number of moles in the limiting reagent. 4 x 0867= 3.468. Finally, we multiply this result by the GFW of the product.
Incorrect 3 - Finding the Limiting Reagent
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Finding the Limiting Reagent. Finding the limiting reagent if 44.2 grams of P were reacted with 622 grams of Br2. First we find the GFW of each reactant. Next we divide the number of grams of each reactant by the GFW. Finally, we multiply each of the results by the coefficient of the other reactant/. 142 x 3= 4.26. 388 x 2= 7.775. Because 4 .26. Is smaller than 7 .775. We know that the limiting reagent is P. Create a free website.
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Bio II Personal Inventory Form. Disease and Travel Websites. Chemistry Lunch Hours and Make-Up Labs. Chemistry Personal Inventory Form. First Day of School. You may have never had to ask for extra practice in the past, but sometimes it's necessary in chemistry. Below is a selection of good websites with practice problems and other resources. If you find a great website that you think other students would benefit from, send me an email with the link and I'll post it on this page! Here's the site for you!
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Finding the Limiting Reagent - Home
Finding the Limiting Reagent. You're in the park with a few of your friends and you want to play a game of football. You decide that the most fair way to split up the teams is to have an even number of boys and girls on each side. There are ten boys, so there can be five of them on each team. But here's the problem, There are only nine girls! In this situation, the limiting reagen. T is the number of girls because there aren't enough girls to have an even second team. Finding the Limiting Reagent. Finall...
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