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Math stuff

Working through problems in stats, probability and other math disciplines as part of my self-study plan. Sunday, August 21, 2011. How To Prove It - Chapter 4 - 4.1. Relations - Ordered Pairs and Cartesian Products. A) T = {(a, b) ∈ P x P a is a parent of b). B) T = {(c, u) ∈ C x U there is someone who lives in c and attends u}. A) T = {(p, c) ∈ P x C p lives in c}. B) T = {(p, n) ∈ C x N the population of p is n}. A) Samples (x, y) = (0, -2), (1, -2), (-1, 0). C) Samples (x, y) = (0, -2), (1, 1). X, y) &...

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Math stuff | statsprob.blogspot.com Reviews
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Working through problems in stats, probability and other math disciplines as part of my self-study plan. Sunday, August 21, 2011. How To Prove It - Chapter 4 - 4.1. Relations - Ordered Pairs and Cartesian Products. A) T = {(a, b) ∈ P x P a is a parent of b). B) T = {(c, u) ∈ C x U there is someone who lives in c and attends u}. A) T = {(p, c) ∈ P x C p lives in c}. B) T = {(p, n) ∈ C x N the population of p is n}. A) Samples (x, y) = (0, -2), (1, -2), (-1, 0). C) Samples (x, y) = (0, -2), (1, 1). X, y) &...
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1 math stuff
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4 revised givens
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8 posted by
9 hrishikesh
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Math stuff | statsprob.blogspot.com Reviews

https://statsprob.blogspot.com

Working through problems in stats, probability and other math disciplines as part of my self-study plan. Sunday, August 21, 2011. How To Prove It - Chapter 4 - 4.1. Relations - Ordered Pairs and Cartesian Products. A) T = {(a, b) ∈ P x P a is a parent of b). B) T = {(c, u) ∈ C x U there is someone who lives in c and attends u}. A) T = {(p, c) ∈ P x C p lives in c}. B) T = {(p, n) ∈ C x N the population of p is n}. A) Samples (x, y) = (0, -2), (1, -2), (-1, 0). C) Samples (x, y) = (0, -2), (1, 1). X, y) &...

INTERNAL PAGES

statsprob.blogspot.com statsprob.blogspot.com
1

Math stuff: How To Prove It - Chapter 4 - 4.1

http://www.statsprob.blogspot.com/2011/08/how-to-prove-it-chapter-4-41.html

Working through problems in stats, probability and other math disciplines as part of my self-study plan. Sunday, August 21, 2011. How To Prove It - Chapter 4 - 4.1. Relations - Ordered Pairs and Cartesian Products. A) T = {(a, b) ∈ P x P a is a parent of b). B) T = {(c, u) ∈ C x U there is someone who lives in c and attends u}. A) T = {(p, c) ∈ P x C p lives in c}. B) T = {(p, n) ∈ C x N the population of p is n}. A) Samples (x, y) = (0, -2), (1, -2), (-1, 0). C) Samples (x, y) = (0, -2), (1, 1). X, y) &...

2

Math stuff: How To Prove It - Chapter 3 - 3.2

http://www.statsprob.blogspot.com/2011/08/how-to-prove-it-chapter-3-32.html

Working through problems in stats, probability and other math disciplines as part of my self-study plan. Tuesday, August 2, 2011. How To Prove It - Chapter 3 - 3.2. Proofs involving negations and conditionals. P → Q - i. Q → R - ii. P → R. Suppose P. Then from (i), Q. Since Q, from (ii), we have R. Hence if P then R. P → R. 172;R → (P → ¬Q). P → (Q → R). From the given,. 172;R → (P → ¬Q). P → ¬Q). Since we know P, we also know now that ¬Q. Hence, ¬R led to ¬Q. 172;R → ¬Q. Q → R. P led to Q → R,. Or b 1 o...

3

Math stuff: April 2011

http://www.statsprob.blogspot.com/2011_04_01_archive.html

Working through problems in stats, probability and other math disciplines as part of my self-study plan. Friday, April 29, 2011. How To Prove It - Chapter 1 - 1.2. P ∨ Q. 8743; ¬ Q) (De Morgan's Law). P ↓ Q. P ↓ Q = ¬ P ∧¬ Q. 172; (P ∨ Q). Truth table verification -. P ↓ Q. I) ¬P = ¬P ∧ ¬P. P ↓ P. P ↓ Q. From the previous ones). 172; ( P ∨ Q). So, ( P ∨ Q). P ↓ Q). P ↓ Q). P ↓ Q). 8743; Q) = ¬(¬. 172; ( ¬. From the previous one). 172; (¬ (¬. P ↓ P) ↓ (Q ↓ Q). 172; P ∨. 172;P = ¬ (P ∧ P). 172; P ∨. Saturd...

4

Math stuff: How To Prove It - Chapter 3 - 3.4

http://www.statsprob.blogspot.com/2011/08/how-to-prove-it-chapter-3-34.html

Working through problems in stats, probability and other math disciplines as part of my self-study plan. Tuesday, August 9, 2011. How To Prove It - Chapter 3 - 3.4. Proofs involving Conjunctions and Biconditionals. Note: A lot of the first few problems are of the same type. Skipped the similar ones. 8704;x(P(x) ∧ Q(x). 8704;x P(x) ∧ ∀x Q(x). Let ∀x(P(x) ∧ Q(x). So for an arbitrary y, P(y) ∧ Q(y). Hence, P(y). So ∀x P(x) is true. So is ∀x Q(x). So, for arbitrary x, P(x) and Q(x) are true. A ⊆ B. Is even i...

5

Math stuff: August 2011

http://www.statsprob.blogspot.com/2011_08_01_archive.html

Working through problems in stats, probability and other math disciplines as part of my self-study plan. Sunday, August 21, 2011. How To Prove It - Chapter 4 - 4.1. Relations - Ordered Pairs and Cartesian Products. A) T = {(a, b) ∈ P x P a is a parent of b). B) T = {(c, u) ∈ C x U there is someone who lives in c and attends u}. A) T = {(p, c) ∈ P x C p lives in c}. B) T = {(p, n) ∈ C x N the population of p is n}. A) Samples (x, y) = (0, -2), (1, -2), (-1, 0). C) Samples (x, y) = (0, -2), (1, 1). X, y) &...

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statsprob.blogspot.com statsprob.blogspot.com

Math stuff

Working through problems in stats, probability and other math disciplines as part of my self-study plan. Sunday, August 21, 2011. How To Prove It - Chapter 4 - 4.1. Relations - Ordered Pairs and Cartesian Products. A) T = {(a, b) ∈ P x P a is a parent of b). B) T = {(c, u) ∈ C x U there is someone who lives in c and attends u}. A) T = {(p, c) ∈ P x C p lives in c}. B) T = {(p, n) ∈ C x N the population of p is n}. A) Samples (x, y) = (0, -2), (1, -2), (-1, 0). C) Samples (x, y) = (0, -2), (1, 1). X, y) &...

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